Example: To convert 5 femtonewton (force) to joule/centimeter (force), multiply 5 by 10000000000000 to get 5.0000e+13 f_J/cm (5.0000e+13 f_J/cm).
f_fN | f_J/cm |
---|---|
4 f_fN | 4.0000e+13 f_J/cm (4.0000e+13 f_J/cm) |
5 f_fN | 5.0000e+13 f_J/cm (5.0000e+13 f_J/cm) |
6 f_fN | 6.0000e+13 f_J/cm (6.0000e+13 f_J/cm) |
7 f_fN | 7.0000e+13 f_J/cm (7.0000e+13 f_J/cm) |
8 f_fN | 8.0000e+13 f_J/cm (8.0000e+13 f_J/cm) |
9 f_fN | 9.0000e+13 f_J/cm (9.0000e+13 f_J/cm) |
10 f_fN | 1.0000e+14 f_J/cm (1.0000e+14 f_J/cm) |
11 f_fN | 1.1000e+14 f_J/cm (1.1000e+14 f_J/cm) |
12 f_fN | 1.2000e+14 f_J/cm (1.2000e+14 f_J/cm) |
13 f_fN | 1.3000e+14 f_J/cm (1.3000e+14 f_J/cm) |
14 f_fN | 1.4000e+14 f_J/cm (1.4000e+14 f_J/cm) |
15 f_fN | 1.5000e+14 f_J/cm (1.5000e+14 f_J/cm) |
16 f_fN | 1.6000e+14 f_J/cm (1.6000e+14 f_J/cm) |
17 f_fN | 1.7000e+14 f_J/cm (1.7000e+14 f_J/cm) |
18 f_fN | 1.8000e+14 f_J/cm (1.8000e+14 f_J/cm) |