Example: To convert 5 ton-force (long) to decinewton (force), multiply 5 by 0.00001003611353125 to get 5.0181e-5 f_dN (5.0181e-5 f_dN).
f_tf_uk | f_dN |
---|---|
3 f_tf_uk | 3.0108e-5 f_dN (3.0108e-5 f_dN) |
4 f_tf_uk | 4.0144e-5 f_dN (4.0144e-5 f_dN) |
5 f_tf_uk | 5.0181e-5 f_dN (5.0181e-5 f_dN) |
6 f_tf_uk | 6.0217e-5 f_dN (6.0217e-5 f_dN) |
7 f_tf_uk | 7.0253e-5 f_dN (7.0253e-5 f_dN) |
8 f_tf_uk | 8.0289e-5 f_dN (8.0289e-5 f_dN) |
9 f_tf_uk | 9.0325e-5 f_dN (9.0325e-5 f_dN) |
10 f_tf_uk | 0.0001 f_dN (1.0036e-4 f_dN) |
11 f_tf_uk | 0.0001 f_dN (1.1040e-4 f_dN) |
12 f_tf_uk | 0.0001 f_dN (1.2043e-4 f_dN) |
13 f_tf_uk | 0.0001 f_dN (1.3047e-4 f_dN) |
14 f_tf_uk | 0.0001 f_dN (1.4051e-4 f_dN) |
15 f_tf_uk | 0.0002 f_dN (1.5054e-4 f_dN) |
16 f_tf_uk | 0.0002 f_dN (1.6058e-4 f_dN) |
17 f_tf_uk | 0.0002 f_dN (1.7061e-4 f_dN) |