Example: To convert 5 piconewton (force) to joule/meter (force), multiply 5 by 1000000000000 to get 5.0000e+12 f_J/m (5.0000e+12 f_J/m).
f_pN | f_J/m |
---|---|
3 f_pN | 3.0000e+12 f_J/m (3.0000e+12 f_J/m) |
4 f_pN | 4.0000e+12 f_J/m (4.0000e+12 f_J/m) |
5 f_pN | 5.0000e+12 f_J/m (5.0000e+12 f_J/m) |
6 f_pN | 6.0000e+12 f_J/m (6.0000e+12 f_J/m) |
7 f_pN | 7.0000e+12 f_J/m (7.0000e+12 f_J/m) |
8 f_pN | 8.0000e+12 f_J/m (8.0000e+12 f_J/m) |
9 f_pN | 9.0000e+12 f_J/m (9.0000e+12 f_J/m) |
10 f_pN | 1.0000e+13 f_J/m (1.0000e+13 f_J/m) |
11 f_pN | 1.1000e+13 f_J/m (1.1000e+13 f_J/m) |
12 f_pN | 1.2000e+13 f_J/m (1.2000e+13 f_J/m) |
13 f_pN | 1.3000e+13 f_J/m (1.3000e+13 f_J/m) |
14 f_pN | 1.4000e+13 f_J/m (1.4000e+13 f_J/m) |
15 f_pN | 1.5000e+13 f_J/m (1.5000e+13 f_J/m) |
16 f_pN | 1.6000e+13 f_J/m (1.6000e+13 f_J/m) |
17 f_pN | 1.7000e+13 f_J/m (1.7000e+13 f_J/m) |