Example: To convert 5 kilogram-force (force) to decinewton (force), multiply 5 by 0.010197162129779 to get 0.051 f_dN (5.0986e-2 f_dN).
f_kgf | f_dN |
---|---|
3 f_kgf | 0.0306 f_dN (3.0591e-2 f_dN) |
4 f_kgf | 0.0408 f_dN (4.0789e-2 f_dN) |
5 f_kgf | 0.051 f_dN (5.0986e-2 f_dN) |
6 f_kgf | 0.0612 f_dN (6.1183e-2 f_dN) |
7 f_kgf | 0.0714 f_dN (7.1380e-2 f_dN) |
8 f_kgf | 0.0816 f_dN (8.1577e-2 f_dN) |
9 f_kgf | 0.0918 f_dN (9.1774e-2 f_dN) |
10 f_kgf | 0.102 f_dN (1.0197e-1 f_dN) |
11 f_kgf | 0.1122 f_dN (1.1217e-1 f_dN) |
12 f_kgf | 0.1224 f_dN (1.2237e-1 f_dN) |
13 f_kgf | 0.1326 f_dN (1.3256e-1 f_dN) |
14 f_kgf | 0.1428 f_dN (1.4276e-1 f_dN) |
15 f_kgf | 0.153 f_dN (1.5296e-1 f_dN) |
16 f_kgf | 0.1632 f_dN (1.6315e-1 f_dN) |
17 f_kgf | 0.1734 f_dN (1.7335e-1 f_dN) |