Example: To convert 5 dekanewton (force) to newton (force), multiply 5 by 0.1 to get 0.5 f_N (5.0000e-1 f_N).
f_daN | f_N |
---|---|
3 f_daN | 0.3 f_N (3.0000e-1 f_N) |
4 f_daN | 0.4 f_N (4.0000e-1 f_N) |
5 f_daN | 0.5 f_N (5.0000e-1 f_N) |
6 f_daN | 0.6 f_N (6.0000e-1 f_N) |
7 f_daN | 0.7 f_N (7.0000e-1 f_N) |
8 f_daN | 0.8 f_N (8.0000e-1 f_N) |
9 f_daN | 0.9 f_N (9.0000e-1 f_N) |
10 f_daN | 1 f_N (1.0000e+0 f_N) |
11 f_daN | 1.1 f_N (1.1000e+0 f_N) |
12 f_daN | 1.2 f_N (1.2000e+0 f_N) |
13 f_daN | 1.3 f_N (1.3000e+0 f_N) |
14 f_daN | 1.4 f_N (1.4000e+0 f_N) |
15 f_daN | 1.5 f_N (1.5000e+0 f_N) |
16 f_daN | 1.6 f_N (1.6000e+0 f_N) |
17 f_daN | 1.7 f_N (1.7000e+0 f_N) |