Example: To convert 5 decinewton (force) to pond (force), multiply 5 by 0.09806650000000272 to get 0.4903 f_p (4.9033e-1 f_p).
f_dN | f_p |
---|---|
3 f_dN | 0.2942 f_p (2.9420e-1 f_p) |
4 f_dN | 0.3923 f_p (3.9227e-1 f_p) |
5 f_dN | 0.4903 f_p (4.9033e-1 f_p) |
6 f_dN | 0.5884 f_p (5.8840e-1 f_p) |
7 f_dN | 0.6865 f_p (6.8647e-1 f_p) |
8 f_dN | 0.7845 f_p (7.8453e-1 f_p) |
9 f_dN | 0.8826 f_p (8.8260e-1 f_p) |
10 f_dN | 0.9807 f_p (9.8067e-1 f_p) |
11 f_dN | 1.0787 f_p (1.0787e+0 f_p) |
12 f_dN | 1.1768 f_p (1.1768e+0 f_p) |
13 f_dN | 1.2749 f_p (1.2749e+0 f_p) |
14 f_dN | 1.3729 f_p (1.3729e+0 f_p) |
15 f_dN | 1.471 f_p (1.4710e+0 f_p) |
16 f_dN | 1.5691 f_p (1.5691e+0 f_p) |
17 f_dN | 1.6671 f_p (1.6671e+0 f_p) |