Example: To convert 5 dekanewton (force) to newton (force), multiply 5 by 0.1 to get 0.5 f_N (5.0000e-1 f_N).
f_daN | f_N |
---|---|
20 f_daN | 2 f_N (2.0000e+0 f_N) |
21 f_daN | 2.1 f_N (2.1000e+0 f_N) |
22 f_daN | 2.2 f_N (2.2000e+0 f_N) |
23 f_daN | 2.3 f_N (2.3000e+0 f_N) |
24 f_daN | 2.4 f_N (2.4000e+0 f_N) |
25 f_daN | 2.5 f_N (2.5000e+0 f_N) |
26 f_daN | 2.6 f_N (2.6000e+0 f_N) |
27 f_daN | 2.7 f_N (2.7000e+0 f_N) |
28 f_daN | 2.8 f_N (2.8000e+0 f_N) |
29 f_daN | 2.9 f_N (2.9000e+0 f_N) |
30 f_daN | 3 f_N (3.0000e+0 f_N) |
31 f_daN | 3.1 f_N (3.1000e+0 f_N) |
32 f_daN | 3.2 f_N (3.2000e+0 f_N) |
33 f_daN | 3.3 f_N (3.3000e+0 f_N) |
34 f_daN | 3.4 f_N (3.4000e+0 f_N) |