Example: To convert 5 joule/centimeter (force) to petanewton (force), multiply 5 by 100000000000000000 to get 5.0000e+17 f_PN (5.0000e+17 f_PN).
f_J/cm | f_PN |
---|---|
2 f_J/cm | 2.0000e+17 f_PN (2.0000e+17 f_PN) |
3 f_J/cm | 3.0000e+17 f_PN (3.0000e+17 f_PN) |
4 f_J/cm | 4.0000e+17 f_PN (4.0000e+17 f_PN) |
5 f_J/cm | 5.0000e+17 f_PN (5.0000e+17 f_PN) |
6 f_J/cm | 6.0000e+17 f_PN (6.0000e+17 f_PN) |
7 f_J/cm | 7.0000e+17 f_PN (7.0000e+17 f_PN) |
8 f_J/cm | 8.0000e+17 f_PN (8.0000e+17 f_PN) |
9 f_J/cm | 9.0000e+17 f_PN (9.0000e+17 f_PN) |
10 f_J/cm | 1.0000e+18 f_PN (1.0000e+18 f_PN) |
11 f_J/cm | 1.1000e+18 f_PN (1.1000e+18 f_PN) |
12 f_J/cm | 1.2000e+18 f_PN (1.2000e+18 f_PN) |
13 f_J/cm | 1.3000e+18 f_PN (1.3000e+18 f_PN) |
14 f_J/cm | 1.4000e+18 f_PN (1.4000e+18 f_PN) |
15 f_J/cm | 1.5000e+18 f_PN (1.5000e+18 f_PN) |
16 f_J/cm | 1.6000e+18 f_PN (1.6000e+18 f_PN) |