Example: To convert 5 dekanewton (force) to pond (force), multiply 5 by 0.0009806650000000272 to get 0.0049 f_p (4.9033e-3 f_p).
f_daN | f_p |
---|---|
1 f_daN | 0.001 f_p (9.8067e-4 f_p) |
2 f_daN | 0.002 f_p (1.9613e-3 f_p) |
3 f_daN | 0.0029 f_p (2.9420e-3 f_p) |
4 f_daN | 0.0039 f_p (3.9227e-3 f_p) |
5 f_daN | 0.0049 f_p (4.9033e-3 f_p) |
6 f_daN | 0.0059 f_p (5.8840e-3 f_p) |
7 f_daN | 0.0069 f_p (6.8647e-3 f_p) |
8 f_daN | 0.0078 f_p (7.8453e-3 f_p) |
9 f_daN | 0.0088 f_p (8.8260e-3 f_p) |
10 f_daN | 0.0098 f_p (9.8067e-3 f_p) |
11 f_daN | 0.0108 f_p (1.0787e-2 f_p) |
12 f_daN | 0.0118 f_p (1.1768e-2 f_p) |
13 f_daN | 0.0127 f_p (1.2749e-2 f_p) |
14 f_daN | 0.0137 f_p (1.3729e-2 f_p) |
15 f_daN | 0.0147 f_p (1.4710e-2 f_p) |